commented out barcode lengths by library because it takes up a lot of space and isn...

diff --git a/mig-xml/evergreen_staged_report.xml b/mig-xml/evergreen_staged_report.xml
index 564b741..7e9fce3 100644 (file)
--- a/mig-xml/evergreen_staged_report.xml
+++ b/mig-xml/evergreen_staged_report.xml
@@ -386,14 +386,14 @@
         <query>SELECT COUNT(ac.id), acl.name, aou.name, ac.x_migrate::TEXT FROM asset_copy_legacy ac JOIN asset.copy_location acl ON acl.id = ac.location JOIN actor.org_unit aou ON aou.id = ac.circ_lib GROUP BY 2, 3, 4 ORDER BY 2, 3, 4</query>
     </report>
 
-    <report>
+    <!-- report>
         <name>asset_barcode_lengths</name>
         <report_title>Barcode Lengths by Library</report_title>
         <tag>assets</tag>
         <iteration>0</iteration>
         <heading>Count of Barcode.Barcode Length.Library</heading>
         <query>SELECT COUNT(ac.id), LENGTH(ac.barcode), aou.name FROM asset_copy_legacy ac JOIN actor.org_unit aou ON aou.id = ac.circ_lib WHERE ac.x_migrate = TRUE GROUP BY 2, 3 ORDER BY 3, 2</query>
-    </report>
+    </report -->
 
     <report>
         <name>asset_barcode_patterns</name>
@@ -873,8 +873,8 @@ id = ac_sc.owner GROUP BY 2,3 ORDER BY 2,3</query>
         <heading>Count of Barcodes (greater than 10).Left 60% of Characters</heading>
         <query>SELECT COUNT(acard.id), LEFT(acard.barcode,(ROUND(LENGTH(acard.barcode)*.6))::INT) FROM actor_card acard GROUP BY 2 HAVING COUNT(acard.id) > 10 ORDER BY 2</query>
     </report>
-
-    <report>
+ 
+   <report>
         <name>usr_barcode_collisions</name>
         <report_title>Patron Barcode Collisions</report_title>
         <tag>actors</tag>